Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Fully explain step-by-step Questions number one a,b,c,d solve for all required

Fully Explain Stepbystep Questions Number One Abcd Solve For All Required class=

Sagot :

(1) The equation is

[tex]v_2=v_1+a\Delta t[/tex]

For v_1,

[tex]\begin{gathered} v_2=v_1+a\Delta t \\ Subtract\text{ a}\Delta t\text{ on both sides.} \\ v_2-a\Delta t=v_1+a\Delta t-a\Delta t \\ v_2-a\Delta t=v_1 \end{gathered}[/tex]

For a,

[tex]\begin{gathered} v_2=v_1+a\Delta t \\ \text{Subtract v}_1\text{ on both sides} \\ v_2-v_1=v_1-v_1+a\Delta t \\ v_2-v_1=a\Delta t \\ \text{Divide }\Delta t\text{ on both sides.} \\ \frac{v_2-v_1}{\Delta t}=a\frac{\Delta t}{\Delta t} \\ \frac{v_2-v_1}{\Delta t}=a \end{gathered}[/tex]

For time,

[tex]\begin{gathered} v_2=v_1+a\Delta t \\ \text{Subtract v}_1\text{ on both sides} \\ v_2-v_1=v_1-v_1+a\Delta t \\ v_2-v_1=a\Delta t \\ \text{Divide }a\text{ on both sides.} \\ \frac{v_2-v_1}{a}=\frac{a}{a}\Delta t \\ \frac{v_2-v_1}{a}=\Delta t \end{gathered}[/tex]

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.