Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

1. An input-output table has constant differences. When the input is 3, the output is 10. When the input is 7, the output is 24. a. Find the constant difference. b. Find the output when the input is 0. C. Find the linear function that fits the table.

Sagot :

a)7,17

b)-25

c)

[tex]y=3.5x-25[/tex]

Explanation

table

a) differences

10-3=7

24-7=17

Step 1

find the slope

[tex]\begin{gathered} \text{slope}=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}[/tex]

Let

P1(3,10)

p2(7,24)

replace,

[tex]\begin{gathered} \text{slope}=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{24-10}{7-3}=\frac{14}{4}=\frac{7}{2} \\ \text{slope}=\frac{7}{2} \end{gathered}[/tex]

Step 2

find the equation

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-10=\frac{7}{2}(x-10) \\ y-10=\frac{7}{2}x-\frac{70}{2} \\ y=\frac{7}{2}x-\frac{70}{2}+10 \\ y=3.5x-25 \end{gathered}[/tex]

Step 3

when x=0

[tex]\begin{gathered} y=3.5x-25 \\ y=3.5\cdot0-25 \\ y=-25 \end{gathered}[/tex]

I hope this helps you