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Select the correct answer torm eacn arop-down menu.
Given: m/AOB = 42°
m/EOF= 66°
Prove: m/COD = 72°
A
B
m
E
Complete the proof.
It is given that m/AOB
m/BOC 66°. By the
m/AOC + m/COD = 180°. After application of the
42° and m/EOF 66°. By the
m/AOC
108, and by the
ZEOF ZBOC. Therefore,
m/COD= 72°.

Select The Correct Answer Torm Eacn Aropdown Menu Given MAOB 42 MEOF 66 Prove MCOD 72 A B M E Complete The Proof It Is Given That MAOB MBOC 66 By The MAOC MCOD class=

Sagot :

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