Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

No clue on how to do these or how to show all my work and unit cancellations.

No Clue On How To Do These Or How To Show All My Work And Unit Cancellations class=

Sagot :

Question 16:

We are given the following balanced equation: (Remember to always balance the equation)

[tex]2HNO_3+Mg(OH)_2\rightarrow Mg(NO_3)_2+2H_2O[/tex]

We are also told that Mg(OH)2 is in excess, meaning HNO3 is the limiting reactant, we will use its moles to find the number of moles of Mg(NO3)2, then we can convert that to mass.

The ratio between HNO3 and Mg(NO3)2 is 2:1

Therefore the number of moles of Mg(NO3)2 = 8.00 mol x (1/2) = 4.00 mol

Now we can convert the number of moles of Mg(NO3)2 to mass: molar mass of Mg(NO3)2 = 148,3 g/mol

[tex]\frac{8.00\text{ mol x 1}}{2}\text{ x }\frac{148.3\text{ g}}{1\text{ mol}}\text{ = 592 g}[/tex]

So the mol will cancel the mol, then you will be left with g.

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.