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Sagot :
Answer:
The final temperature is 3,952K. (The closest option is 3,950K).
Explanation:
The given information from the exercise is:
- Initial pressure (P1): 300.6mmHg
- Initial volume (V1): 1.23L
- Initial temperature (T1): 218.5K
- Final volume (V2): 8.32L
- Final pressure (P2): 802.75mmHg
We can calculate the final temperature (T2), by replacing the values of P1, V1, T1, V2 and P2 in the following formula of Ideal Gases:
[tex]\begin{gathered} \frac{P_1*V_1}{T_1}=\frac{P_2*V_2}{T_2} \\ \frac{300.6mmHg*1.23L}{218.5K}=\frac{802.75mmHg*8.32L}{T_2} \\ 1.69\frac{mmHgL}{K}=\frac{6,678.88mmHgL}{T_2} \\ T_2=\frac{6,678.88mmHgL}{1.69\frac{mmHgL}{K}} \\ T_2=3,952K \end{gathered}[/tex]So, the final temperature is 3,952K. (The closest option is 3,950K).
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