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Sagot :
Given data:
* The weight of the rocket is 1470.39 N.
* The distance traveled by the rocket is 1522.64 m.
* The time taken by the rocket is 2.11 seconds.
Solution:
The velocity of the rocket in terms of the distance and time is,
[tex]\begin{gathered} v=\frac{\text{distance}}{\text{time}} \\ v=\frac{1522.64}{2.11} \\ v=721.63\text{ m/s} \end{gathered}[/tex]The mass of the rocket from the weight is,
[tex]\begin{gathered} mg=1470.39 \\ m=\frac{1470.39}{g} \end{gathered}[/tex]where g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} m=\frac{1470.39}{9.8} \\ m=150.04\text{ kg} \end{gathered}[/tex]The kinetic energy of the rocket in terms of mass and velocity of the rocket is,
[tex]\begin{gathered} K=\frac{1}{2}mv^2 \\ K=\frac{1}{2}\times150.04\times721.63^2 \\ K=39066654.26\text{ J} \\ K=39.07\times10^6\text{ J} \\ K=39.07\text{ MJ} \end{gathered}[/tex]Thus, the kinetic energy of the rocket is 39.07 MJ.
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