Answered

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Find the value of x that makes A || B.AB5423142 3x10 and 23 = x + 30X=[? ]

Find The Value Of X That Makes A BAB5423142 3x10 And 23 X 30X class=

Sagot :

∠2 and ∠3 are alternate interior angles. In order to A II B, the alternate interior angles must be equal.

Then,

[tex]\begin{gathered} \angle2=\operatorname{\angle}3 \\ 3x-10=x+30 \end{gathered}[/tex]

To find x, subtract x from both sides of the equation:

[tex]\begin{gathered} 3x-10-x=x+30-x \\ 3x-x-10=x-x+30 \\ 2x-10=30 \end{gathered}[/tex]

Now, add 10 to both sides of the equation:

[tex]\begin{gathered} 2x-10+10=30+10 \\ 2x=40 \end{gathered}[/tex]

Finally, divide both sides by 2:

[tex]\begin{gathered} \frac{2x}{2}=\frac{40}{2} \\ x=20 \end{gathered}[/tex]

Answer: x = 20.

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