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Sagot :
The molarity of the solution is 0.209 M.
Molarity is an expression of the concentration of a compound and it is represented in mole/liter.
So, we need to know how many moles tha sample has.
- First, with the molar mass of the NaCl molecule we calculate the number of moles conteined in 9.2g of NaCl:
NaCl molar mass= 58.44g/mol
[tex]\frac{9.2g\text{ . 1mol}}{58.44g}=\text{ 0.157 moles}[/tex]- Second, molarity is expressed in 1 liter, so we calculate the number of moles that are conteined in 1 liter:
[tex]\frac{1L\text{ . 0.157moles}}{0.75L}=0.209\text{ moles}[/tex]- So, the molarity of the solution is 0.209 M.
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