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How do i solve this problem? Hint: The cannonball is being launched vertically upwards, therefore, there is no initial horizontal speed. The given initial speed will also be the initial vertical speed.

How Do I Solve This Problem Hint The Cannonball Is Being Launched Vertically Upwards Therefore There Is No Initial Horizontal Speed The Given Initial Speed Will class=

Sagot :

The initial velocity of the ball is given as 36.0 m/s.

The horizontal component of velocity of ball is given as,

[tex]v_x=v\cos \theta[/tex]

The ball is projected vertically, therefore, the angle made by ball is 90 degree.

Plug in the known values,

[tex]\begin{gathered} v_x=(36.0m/s)cos90^{\circ} \\ =(36.0\text{ m/s)(0)} \\ =0\text{ m/s} \end{gathered}[/tex]

Therefore, the initial horizontal velocity of ball is 0 m/s.

The vertical component of velocity of ball is given as,

[tex]v_y=v\sin \theta[/tex]

Plug in the known values,

[tex]\begin{gathered} v_y=(36.0m/s)\sin 90^{\circ} \\ =(36.0\text{ m/s)(1)} \\ =36.0\text{ m/s} \end{gathered}[/tex]

Therefore, the initial vertical velocity of the ball is 36.0 m/s.

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