We can see from the question that we have the following function:
[tex]f(x)=\frac{3x+2}{x+1}[/tex]And we need to find the rate of change from x = 0 to x = 2.
1. To find the average rate of change, we need to remember the formula to find it:
[tex]\text{ Average rate of change}=\frac{\text{ change in y}}{\text{ change in x}}=\frac{y_2-y_1}{x_2-x_1}[/tex]And we also have the average rate of change for a function, f(x) between x = a and x = b is given by:
[tex]\text{ Average rate of change}=\frac{\text{ change in y}}{\text{ change in x}}=\frac{f(b)-f(a)}{b-a}[/tex]2. Then we have that the average rate of change between x = 0 and x = 2 is as follows:
[tex]\begin{gathered} x=0,x=2 \\ \\ \text{ Average rate of change}=\frac{f(2)-f(0)}{2-0} \\ \end{gathered}[/tex]3. However, we need to find the values for the function when f(2) and f(0). Then we have:
[tex]\begin{gathered} f(x)=\frac{3x+2}{x+1} \\ \\ x=2\Rightarrow f(2)=\frac{3(2)+2}{2+1}=\frac{6+2}{3}=\frac{8}{3} \\ \\ \therefore f(2)=\frac{8}{3} \end{gathered}[/tex]And we also have:
[tex]\begin{gathered} x=0 \\ \\ f(0)=\frac{3x+2}{x+1}=\frac{3(0)+2}{0+1}=\frac{0+2}{1}=\frac{2}{1}=2 \\ \\ \therefore f(0)=2 \end{gathered}[/tex]4. Finally, the average rate of change is given by:
[tex]\begin{gathered} A_{rateofchange}=\frac{f(2)-f(0)}{2-0}=\frac{\frac{8}{3}-2}{2}=\frac{\frac{8}{3}-2}{2}=\frac{\frac{8}{3}-\frac{6}{3}}{2}=\frac{\frac{2}{3}}{2}=\frac{2}{3}*\frac{1}{2}=\frac{1}{3} \\ \\ \therefore A_{rateofchange}=\frac{1}{3} \end{gathered}[/tex]Therefore, in summary, we have that the average rate of change of the function:
[tex]f(x)=\frac{3x+2}{x+1},\text{ between x = 0 to x =2 is: }\frac{1}{3}[/tex]