Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Given:
The pendulum completes one oscillation every 4 seconds.
To find the time period, frequency, and length of the pendulum.
Explanation:
The time period is the time taken to complete one oscillation, so the time period is
[tex]T\text{ = 4 s}[/tex]The frequency will be
[tex]\begin{gathered} f=\frac{1}{T} \\ =\frac{1}{4} \\ =0.25\text{ Hz} \end{gathered}[/tex]The length of the pendulum is
[tex]\begin{gathered} T=2\pi\sqrt{\frac{l}{g}} \\ l=\frac{T^2}{4\pi^2}g \end{gathered}[/tex]Here, g =9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the length will be
[tex]\begin{gathered} l=\frac{(4)^2\times9.8}{4\times(3.14)^2} \\ =3.97\text{ m} \end{gathered}[/tex]Thus, the length of the pendulum is 3,97 m.
Final answer:
The time period is 4 s.
The frequency is 0.25 Hz.
The length of the pendulum is l = 3.97 m.
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
