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There are 38 coins in a collection of 20 paise coins and 25 paise coins. If the total value of the collection is Rupees 8.50, how many of each are there?

Sagot :

We will have the following:

*First:

**We stablish that x will represent the number of 20 paise coins.

**We stablish that y will represent the number of 25 paise coins.

Second: From this we will then have:

[tex]x+y=38[/tex]

&

[tex]20x+25y=850[/tex]

[This 850 is due to the fact that 8.50 Rupees are equal to 850 paise].

*Third: We solve for either x or y in the first equation:

[tex]x=38-y[/tex]

Now, we replace this in the second equation and solve for y:

[tex]20(38-y)+25y=850\Rightarrow760-20y+25y=850[/tex][tex]\Rightarrow5y=90\Rightarrow y=18[/tex]

So, we have that there are 18 25 paise coins.

Now, using this we solve for x in the first equation:

[tex]x+18=38\Rightarrow x=20[/tex]

So, we have that there are 20 20 pais coins.

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