Answered

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(a) How much power (in W) is dissipated in a short circuit of 225 V AC through a resistance of 0.280 Ω? W(b) What current (in A) flows? A

Sagot :

Let's name some variables:

V: voltage; V = 225V

R: resistance; R = 0.28 ohm

I: current

P: power

Let's use this equation first to solve for P:

P = V^2/R

Plugging in variables:

P = 225^2/0.28

P = 180803.57 W = 180.80357 kW

We can use the following to solve for I:

V = IR

225 = I*0.28

I = 803.571 A = 803571 mA

We can also use this method:

Now that we have P, we can use this to solve for I:

P = IV

Plugging in the known variables:

180803.57 = 225*I

I = 803.571 A = 803571 mA

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