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Sagot :
Given, the fraction of children, C=5/8.
The fraction of adults, A=3/8.
Therefore 5/8 is more than 3/8 is given by,
[tex]\begin{gathered} \text{Percent}=\frac{C-A}{A}\times100 \\ =\frac{\frac{5}{8}-\frac{3}{8}}{\frac{3}{8}}\times100 \\ =\frac{\frac{5-3}{8}}{\frac{3}{8}}\times100 \\ =\frac{2}{3}\times100 \\ =66.67 \end{gathered}[/tex]Therefore, 5/8 is more than 3/8 by 66.67%.
In each of the figures, there are 8 boxes. In the first figure showing the fraction of children, two boxes are shaded more than the figure for adults. In the second figure for the fraction of adults, only 3 boxed are shaded.
So, the % by which 5/8 is more than 3/8 can be found as
[tex]\begin{gathered} \text{percentage}=\frac{Number\text{ of extra shaded boxes in first figure}}{\text{Number of shaded boxes in second figure}}\times100 \\ =\frac{2}{3}\times100=66.67 \end{gathered}[/tex]5/8 is 5 parts of 8. 3/8 is 3 parts of 8. So, if the total number of people is 8, five people are children and three people are adults.
So, number of children is 2 more than the number of adults, whose number is 3.
Therefore, the fraction for number of children more than the adults with respect to the number of adults is 2/3. In percentage,
[tex]\text{percentage}=\frac{2}{3}\times100=66.67[/tex]So, 5/8 is more than 3/8 by 66.67%.

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