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Sagot :
Given:
When the price of admission was $19, the attendance was about 1550 customers per week
And, when the price of admission was dropped to $16,
attendance increased to about 2350 per week
Let the attendance = A
And the price = p
The linear equation will be A = mp + b
Where (m) is the slope and (b) is the y-intercept
So,
When p = 19, A = 1550
When p = 16, A = 2350
So,
[tex]m=\frac{2350-1550}{16-19}=\frac{800}{-3}=-\frac{800}{3}[/tex]So,
[tex]A=-\frac{800}{3}p+b[/tex]we will find the value of (b) as follows:
[tex]\begin{gathered} 1550=-\frac{800}{3}\cdot19+b \\ 1550=-\frac{15200}{3}+b \\ b=\frac{19850}{3} \end{gathered}[/tex]So, the answer will be the linear equation is:
[tex]A=\frac{-800}{3}p+\frac{19850}{3}[/tex]
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