Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
We must plot the following exponential function:
[tex]y=f(x)=4^x.^{}[/tex]Replacing the values of x in the function above, we complete the table:
[tex]\begin{gathered} x=-3\rightarrow y=f(-3)=4^{-3}=\frac{1}{64}=0.015625, \\ x=-2\rightarrow y=f(-2)=4^{-2}=\frac{1}{16}=0.0625, \\ x=-1\rightarrow y=f(-1)=4^{-1}=\frac{1}{4}=0.25, \\ x=0\rightarrow y=f(0)=4^0=1, \\ x=1\rightarrow y=f(1)=4^1=4, \\ x=2\rightarrow y=f(2)=4^2=16, \\ x=3\rightarrow y=f(3)=4^3=64. \end{gathered}[/tex]So we have the following points:
• (-3, 1/64) = (-3, 0.015625),
,• (-2, 1/16) = (-2, 0.0625),
,• (-1, 1/4) = (-1, 0.25),
,• (0, 1),
,• (1, 4),
,• (1, 16),
,• (1, 64).
Now, plotting each point (x, y) and joining them, we get the following graph:
One clarification: the label of the points in the graph have been rounded.
Answer
The points of the table are:
• (-3, 1/64)
,• (-2, 1/16)
,• (-1, 1/4)
,• (0, 1),
,• (1, 4),
,• (1, 16),
,• (1, 64).
The graph of the points and the function is:
One clarification: the label of the points in the graph have been rounded.
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.