Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

You have two spinners each with three sections of equal size, one labeled with the numbers 1,2,3 and the others 2,4,6. You spin both and observe the numbers. Let X be the sum of the two numbers. In the game you are playing, you win if you get a sum of at least a 600 in 100 spins. If not you lose, should I play?

You Have Two Spinners Each With Three Sections Of Equal Size One Labeled With The Numbers 123 And The Others 246 You Spin Both And Observe The Numbers Let X Be class=

Sagot :

From the table

[tex]\text{Total possible outcomes = 9}[/tex]

we are to find the probability of getting a sum of at least 600 in 100 spins

This means, we need to get a sum of at least 6 in 1 spin

Hence

[tex]\begin{gathered} P(\text{getting a sum of at least }6\text{ in one spin)} \\ =\text{ }\frac{number\text{ of possible outcome}}{total\text{ possible outcome}} \end{gathered}[/tex]

From the table

number of the possible outcome of getting a sum of at least 6 = 5

Therefore

[tex]\begin{gathered} P(\text{getting sum of at least 6 in one spin)} \\ =\text{ }\frac{5}{9} \\ \cong\text{ 0.56} \end{gathered}[/tex]

Since the probability is more than 0.5 then

I can play the game

View image BraxtonQ449069
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.