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what is the 34th term of this seauence 1,9, 17,25,33

Sagot :

Answer : 34th term is 265

Given the following sequence

1, 9, 17, 25, 33

Firstly, we need to find the common difference of the series

Common difference = Larger number - lower number

Common difference = 9 - 1 = 8

17 - 9 = 8

25 - 17 = 8

33 - 25 = 8

Therefore, the common difference = 8

Tn = a + (n - 1 ) d

Where a = first term, n = no of terms, d = common difference

a = 1, n = 34, d = 8

T34 = 1 + (34 - 1) x 8

T34 = 1 + (33) x 8

T34 = 1 + 264

T34 = 265

Therefore, the 34th term is 265

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