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Each part has its own answer & part 2/2 is a continuation of the first part 1/2 :)

Each Part Has Its Own Answer Amp Part 22 Is A Continuation Of The First Part 12 class=

Sagot :

Answer:

Explanations:

1) According to the first question, we are to find the molar mass of Na₂SO₄.

Find the molar mass of each element present on the compound

• Molar mass of Sodium (Na) = 23g/mol

,

• Molar mass of sulfur (S) = 32g/mol

,

• Molar mass of Oxygen (O) = 16g/mol

Get the molar mass of Na₂SO₄.

[tex]\begin{gathered} \text{Molar mass of }Na_{2}SO_{4}=2(23)+32+4(16) \\ \text{Molar mass of }Na_2SO_4=46+32+64 \\ \text{Molar mass of }Na_{2}SO_{4}=142g\text{/mol} \end{gathered}[/tex]

Therefore the molar mass of Na₂SO₄ is 142g/mol

2) The formula for calculating the number of moles of the compound Na₂SO₄ is expressed as:

[tex]n=\text{Molar conc.}\times\text{volume}[/tex]

Given the following parameters:

• Molar concentration = 0.202M = 0.202mol/L

,

• Volume = 784mL= 0.784L

Substitute the given parameters into the formula:

[tex]\begin{gathered} n=0.202\frac{mol}{\cancel{L}}\times0.784\cancel{L} \\ n=0.1584\text{moles} \end{gathered}[/tex]

Hence the number of Na₂SO₄ needed is 0.1584moles.

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