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For a standard normal distribution, find:P(-1.28 < z < 0.8)please solve this question

Sagot :

Consider that:

P(-1.28 < z < 0.8) = P(z < 0.8) - P(z < -1.28)

By using a normal distribution table for z-scores, you have:

The first table give us the probability P(z<-1.28) = 0.10027 and the seconf table give us the probability P(z < 0.8) = 0.78814

By replacing the previous values into the expression for P(-1.28 < z < 0.8), you obtain:

P(-1.28 < z < 0.8) = 0.78814 - 0.10027 = 0.68787

Hence, the result is 0.68787

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View image RoseannaG651808
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