Answered

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What is the equation in standard form of the line that passes through the point (6,-1) and isparallel to the line represented by 8x + 3y=15?A 8x+3y=-45B 8x-3y = -51C 8x+3y=45D 8x - 3y=51

Sagot :

The slope of the given line is:

[tex]s=-\frac{8}{3}\text{.}[/tex]

Therefore, the slope of a parallel line to the given line must be -8/3.

Using the slope-point formula for the equation of a line we get:

[tex]y-(-1)=-\frac{8}{3}(x-6)\text{.}[/tex]

Taking the above equation to its standard form we get:

[tex]\begin{gathered} y+1=-\frac{8}{3}(x-6), \\ 3y+3=-8(x-6), \\ 3y+3=-8x+48, \\ 8x+3y=48-3, \\ 8x+3y=45. \end{gathered}[/tex]

Answer: Option C.

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