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What is an equation of the line parallel to the line on the graph that passes through (2,25)?

What Is An Equation Of The Line Parallel To The Line On The Graph That Passes Through 225 class=

Sagot :

y=4x+17

Explanation

Step 1

2 equations of lines are parallel if the slope is the same, so

a) find the slope of the graphed line

the slope of a line can by calculated by using

[tex]\begin{gathered} slope=\frac{change\text{ in y }}{change\text{ in x}}=\frac{y_2-y_1}{x_2-x_1} \\ where \\ P1(x_1,y_1) \\ and \\ P2(x_2,y_2) \\ are\text{ 2 points from the line} \end{gathered}[/tex]

so

pick up 2 points from the the line and let

[tex]\begin{gathered} P1(0,10) \\ P2(10,50) \end{gathered}[/tex]

replace and evaluate

[tex]\begin{gathered} slope=\frac{change\text{\imaginaryI ny}}{change\text{\imaginaryI nx}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ slope=\frac{50-10}{10-0}=\frac{40}{10}=4 \end{gathered}[/tex]

hence, the slope of the line is 4

Step 2

now, using the slope and a point we can find the equation of the line

use the point-slope formula, it says

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ where\text{ m is the slope} \\ (x_1,y_1)\text{ is a point from the line} \end{gathered}[/tex]

so

a)let

[tex]\begin{gathered} P1(2,25) \\ sloipe=4 \end{gathered}[/tex]

b) now ,replace and solve for y

[tex]\begin{gathered} y-y_{1}=m(x-x_{1}) \\ y-25=4(x-2) \\ y-25=4x-8 \\ add\text{ 25 in both sides} \\ y-25+25=4x-8+25 \\ y=4x+17 \end{gathered}[/tex]

so, the answer is

y=4x+17

I

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