Answered

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A chemist prepares a solution of copper(II) sulfate CuSO4 by measuring out 27.μmol of copper(II) sulfate into a 300.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's copper(II) sulfate solution. Round your answer to 2 significant digits.

Sagot :

Step 1: Identify the given and do necessary conversions.

• 27.mol of copper ,

we know that 1 = 1*10^-6 mole ,

So, 27.mol*1*10^-6 = 27*10 ^-6 mole of copper.

• Volume of the solution = 300ml ,

300ml/1000ml = 0.3L

Step 2: Calculate the concentration in mol/L

Molarity( M /mole/L) = moles of the solute / volume

=27*10 ^-6 mole/ 0.3 L

=0.00009mol/L

• Therefore ,Concentraion of copper(II) sulfate =9.0x10^-5mol/L

( 2 significant digits)

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