Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

What happens to the graph of y=2x^3+x^2−7x−6 as x heads toward ∞ and −∞?A. as x→∞, y→∞ as x→−∞, y→−∞B. as x→∞, y→∞ as x→−∞, y→∞C. as x→∞, y→−∞ as x→−∞, y→−∞D. as x→∞, y→−∞ as x→−∞, y→∞

Sagot :

Answer:

A. as x→∞, y→∞ as x→−∞, y→−∞

Explanation:

Given the function:

[tex]y=2x^3+x^2−7x−6[/tex]

In order to determine the end behavior of f(x), we use the leading coefficient test.

When using the Leading coefficient test, the following rule applies:

• When the ,degree is odd and the leading coefficient is positive,, the graph falls to the left and rises to the right.

,

• When the ,degree is odd and the leading coefficient is negative,, the graph rises to the left and falls to the right.

,

• When the ,degree is even and the leading coefficient is positive,, the graph rises to the left and right.

,

• When the ,degree is even and the leading coefficient is negative,, the graph falls to the left and right.

From the function, f(x):

• The degree of the polynomial = 3 (Odd)

,

• The leading coefficient is 2 (Positive)

Thus, using the 1st rule of the 4 given above, we have that as x→∞, y→∞ as x→−∞, y→−∞.

The correct option is A.

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.