Answered

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The probability that VSU and KSU both win a basketball game in the same week is 47%. Theprobability that VSU wins is 50%. What is the probability that KSU will win given that VSUhas already won?

Sagot :

EXPLANATION

Let the probability that KSU will win a game be Pr(A), and let the probability that VSU wins be Pr(B). Therefore;

[tex]\begin{gathered} Pr(A\cap B)=0.47 \\ Pr(B)=0.5 \end{gathered}[/tex]

We can then use the conditional probability formula below.

[tex]Pr(A|B)=\frac{Pr(A\cap B)}{Pr(B)}[/tex]

Therefore, the probability that KSU will win given that VSU has already won becomes

[tex]Pr(A|B)=\frac{0.47}{0.50}=0.94[/tex]

Answer: 0.94

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