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Sagot :
Answer:
[tex]C_3H_6O_3[/tex]Explanations:
Given the following parameters
Carbon = 40.0%
Hydrogen = 6.71%
Oxygen = 53.29%
Convert to mass
Carbon = 40.0grams
Hydrogen = 6.71grams
Oxygen = 53.29grams
Convert the mass to moles
Mole of carbon = 40.0/12 = 3.33moles
Mole of hydrogen = 6.71/1 = 6.71 moles
Mole of oxygen = 53.29/16 = 3.33moles
Divide by the lowest number of moles
Carbon: 3.33/3.33 = 1
Hydrogen: 6.71/3.33 = 2.01
Oxygen: 3.33/3.33 = 1
Determine the empirical formula
Empirical formula = CH2O
Determine the molecular formula
[tex]\begin{gathered} (CH_2O)_n=90 \\ (12+2(1)+16)n=90 \\ 30n=90 \\ n=\frac{90}{30} \\ n=3 \end{gathered}[/tex][tex](CH_2O)_3=C_3H_6O_3[/tex]Hence the molecular mass of the compound is C3H6O3
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