Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

If the initial concentration of a 400 ml solution is 7% and the solution is diluted down to a concentration of 4.5%, what will the new volume of the solution be?

Sagot :

We have that the dilution equation of concentrated solutions will be equal to:

[tex]C_1V_1=C_2V_2[/tex]

where,

C1 is the initial concentration of the solution = 7%

V1 is the initial volume = 400mL

C2 is the final concentration = 4.5%

V2 is the final volume = ?

We clear Ve and replace the known data:

[tex]\begin{gathered} V_2=\frac{C_1V_1}{C_2} \\ V_2=\frac{7\%\times400mL}{4.5\%}=622mL \end{gathered}[/tex]

Answer: the new volume of the solution will be 622 mL

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.