Answered

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the perimeter of the original rectangle is 16 ft. what is the perimeter of the enlarged rectangle? round to the nearest tenth if necessary.

The Perimeter Of The Original Rectangle Is 16 Ft What Is The Perimeter Of The Enlarged Rectangle Round To The Nearest Tenth If Necessary class=

Sagot :

To calculate the perimeter of the enlarged rectangle, we need to get the breadth first.

The original rectangle is similar to the enlarged rectangle, so the ratio of thier corresponding sides must be equal

Let b represent the breadth of the enlarged rectangle,

[tex]\begin{gathered} \text{ Ratio of corresponding sides is given as } \\ \frac{1.8}{b}=\frac{6.2}{12.4} \\ \text{cross multiply} \\ 6.2b=12.4\text{ x 1.8} \\ 6.2b=22.32 \\ b=\frac{22.32}{6.2} \\ b=3.6\text{ ft} \end{gathered}[/tex]

Now, the length of the enlarged rectangle is 12.4ft while the breadth is 3.6ft

The perimeter = 2(L+B)

= 2(12.4 + 3.6)

=2(16)

=32ft

The perimeter of the enlarged rectangle is 32 ft

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