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b) The slope of a line is 3. The line contains the points (-1,8), and (x, 2).Then x =

Sagot :

The slope between two points (x1,y1) and (x2,y2) is given by:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Plugging the values of the points given and the slope we have that:

[tex]\begin{gathered} \frac{2-8}{x-(-1)}=3 \\ \frac{-6}{x+1}=3 \\ 3(x+1)=-6 \\ x+1=-\frac{6}{3} \\ x+1=-2 \\ x=-2-1 \\ x=-3 \end{gathered}[/tex]

Therefore x=-3