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in the following geometric sequence, find (i) the 7th term; (ii) the nth term:-1/3, 3/4, -9/8, .....

In The Following Geometric Sequence Find I The 7th Term Ii The Nth Term13 34 98 class=

Sagot :

Given the geometric sequence:

[tex]-\frac{1}{2},\frac{3}{4},\frac{-9}{8},\ldots.[/tex]

The common ratio will be:

[tex]r=\frac{3}{4}\div-\frac{1}{2}=\frac{3}{4}\cdot-2=-\frac{3}{2}[/tex]

The general rule of the geometric sequence will be:

[tex]a_n=a_1\cdot r^{n-1}[/tex]

so, a7 will be:

[tex]a_7=-\frac{1}{2}\cdot(-\frac{3}{2})^{7-1}=-\frac{1}{2}\cdot(-\frac{3}{2})^6=-\frac{729}{128}[/tex]

And an will be:

[tex]a_n=(-\frac{1}{2})\cdot(-\frac{3}{2})^{n-1}_{}[/tex]