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Solve for h: A = (1/2)*b*h*O h = 2*A*bO h = A *(b/2)O h = (2*A)/b0 h = (2+b)/A

Sagot :

[tex]\begin{gathered} A=\frac{1}{2}bh \\ \text{cross multiply} \\ 2A=bh \\ \frac{2A}{b}=h \\ \\ h=\frac{2A}{b} \end{gathered}[/tex]

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