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Sagot :
[tex]2(x-6)+7x=5-3(x-2)[/tex]
To solve x, let's eliminate the parenthesis first by multiplying 2 and -3 to it.
[tex]2x-12+7x=5-3x+6[/tex]Next, let's combine all like terms on either side. We will move -3x to the left side of the equation and -12 to the right side of the equation. Note that when a term crosses the equal symbol, the sign reverses. From -3x to +3x and from -12 to +12.
[tex]2x+7x+3x=5+6+12[/tex]Next, add the terms on both sides.
[tex]12x=23[/tex]Lastly, divide both sides by 12 to isolate x.
[tex]\begin{gathered} \frac{12x}{12}=\frac{23}{12} \\ x=\frac{23}{12} \end{gathered}[/tex]The value of x is 23/12.
Let's check if this is right by substituting the value of x to the equation.
[tex]\begin{gathered} 2(\frac{23}{12}-6)+7(\frac{23}{12})=5-3(\frac{23}{12}-2) \\ 2(-\frac{49}{12})+\frac{161}{12}=5-3(-\frac{1}{12}) \\ -\frac{98}{12}+\frac{161}{12}=5+\frac{3}{12} \\ \frac{63}{12}=\frac{63}{12} \\ \frac{21}{4}=\frac{21}{4} \end{gathered}[/tex]Since we got the same 21/4 on both sides of the equation, our x value 23/12 is correct.
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