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Sagot :
Assume that the 2 numbers are x and y, then
Since their sum is 18
That means add x and y, equate the sum by 18
[tex]x+y=18(1)[/tex]Since their difference is 2
That means subtract x and y, equate the difference by 2
[tex]x-y=2(2)[/tex]Add (1) and (2) to eliminate y
[tex]\begin{gathered} (x+x)+(y-y)=(18+2) \\ 2x+0=20 \\ 2x=20 \end{gathered}[/tex]Divide both sides by 2 to find x
[tex]\begin{gathered} \frac{2x}{2}=\frac{20}{2} \\ x=10 \end{gathered}[/tex]Substitute the value of x in (1) to find y
[tex]10+y=18[/tex]Subtract 10 from both sides
[tex]\begin{gathered} 10-10+y=18-10 \\ y=8 \end{gathered}[/tex]The 2 numbers are 10 and 8
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