We are given the function below;
[tex]f(x)=-2x^2-4x[/tex]
PART A
We then proceed to find if the function has a minimum or maximum value. To find if the function has a minimum or maximum value. If the x^2 coefficient is positive, the function has a minimum. If it is negative, the function has a maximum.
ANSWER: From the above, we can see that x^2 is negative, hence the function has a maximum
PART B and C
To find the minimum or maximum value, we would plot the graph of the f(x). The graph can be seen below.
From the graph, the black point helps answer part A and part B.
ANSWER: The function's maximum value is f(x)=2.
This is the point where the slope of the graph is equal to zero
ANSWER: The maximum value then occurs at x= -1
We can also solve this by differentiating the function.
[tex]\begin{gathered} f(x)=-2x^2-4x \\ f^{\prime}(x)=-4x-4 \\ At\xi maxmum\text{ }f^{\prime}(x)=0 \\ -4x-4=0 \\ -4x=4 \\ x=-\frac{4}{4} \\ x=-1 \\ \therefore\text{The max}imum\text{ value occurs at x=-1} \\ \text{Inserting the value of x into the function, we have} \\ f(x)=-2(-1)^2-4(-1) \\ f(x)=-2+4 \\ f(x)=2 \\ \therefore\text{The function max}imum\text{ value is 2} \end{gathered}[/tex]
