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Find the area, to the nearest thousandth, of the standard normal distribution between the given z-scores.z = 1 and z = 1.81

Sagot :

Since this is a normal distribution, the area between the z-scores z₁ = 1 and z₂ = 1.81 is just the probability that the random variable Z is between z₁ and z₂:

[tex]P(z_1\leq Z\leq z_2)=P(z_1\leq Z)-P(z_2\leq Z_{})=P(1\leq Z)-P(1.81\leq Z)[/tex]

Using the values reported on tables for the standardized normal distribution, we know that:

[tex]\begin{gathered} P(1\leq Z)=0.158655 \\ P(1.81\leq Z)=0.035148 \end{gathered}[/tex]

Now, using these results:

[tex]P(z_1\leq Z\leq z_2)=0.158655-0.035148=0.123507[/tex]