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What is the equation of the line that passes through the point (4, 9) with a slope of - 5/8 Write the equation in point-slope form.

Sagot :

the slope of the line is -5/8 and it is passing through (4, 9)

the equation of a line is

[tex]y-9=m(x-4)[/tex]

put m = -5/8

[tex]\begin{gathered} y-9=-\frac{5}{8}(x-4) \\ y-9=-\frac{5}{8}x+\frac{1}{2} \end{gathered}[/tex]

so the equation of line is

y = -5/8 x + (1/2) + 9

y = -5/8 x + 19/2