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A: 502° CB: 6, 681° CC: 6, 135°CD: 47° C

A 502 CB 6 681 CC 6 135CD 47 C class=

Sagot :

The idea behind the problem is solving an equation involving square roots. The equation I'm talking about is

[tex]358=20\cdot\sqrt[]{273+t}[/tex]

(I merely replaced v by 358; what we are supposed to do is to find t). Let's solve it:

1. 20 is multiplying at the right-hand side, let's send it to divide at the left:

[tex]\frac{358}{20}=\sqrt[]{273+t}[/tex]

2. (this is the most important step) Take the power of 2 on both sides:

[tex](\frac{358}{20})^2=273+t[/tex]

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Comment: Remember that

[tex](\sqrt[]{273+t})^2=273+t[/tex]

because square root and powering by two are inverse of each other.

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3. Put the left-hand side in a calculator to get:

[tex]\frac{128164}{400}=273+t[/tex]

4. Let's subtract 273 to the left-hand side:

[tex]320.41-273=t[/tex][tex]47.41\degree C=t[/tex]