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Sagot :
Find an equation of the line parallel to the graph of y = -3x - 11 that passes through the point of (2,4). Write your equation in slope-intercept form.
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Line parallel to the graph of y = -3x - 11
1. The slope-intercept form.
y = mx + b
m= slope
y-intercept is (0, b)
The lines parallel has the same slope (m) = -3
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Using the point-slope form
(y-y1)= m (x-x1)
2. Replacing the point and the slope
(2,4) x1= 2; y1 = 4
(y- 4)= -3 (x- 2)
3. Write your equation in slope-intercept form.
y = -3x +6 +4
y = -3x + 10
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Answer
y = -3x + 10
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