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Find an equation of the line parallel to the graph of y = -3x - 11 that passes through the point of (2,4). Write your equation in slope-intercept form.

Sagot :

Find an equation of the line parallel to the graph of y = -3x - 11 that passes through the point of (2,4). Write your equation in slope-intercept form.​

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Line parallel to the graph of y = -3x - 11

1. The slope-intercept form.

y = mx + b

m= slope

y-intercept is (0, b)

The lines parallel has the same slope (m) = -3

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Using the point-slope form

(y-y1)= m (x-x1)

2. Replacing the point and the slope

(2,4) x1= 2; y1 = 4

(y- 4)= -3 (x- 2)

3. Write your equation in slope-intercept form.​

y = -3x +6 +4

y = -3x + 10

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Answer

y = -3x + 10

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