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for part B how do I find the coordinate for A double prime after the rotation

For Part B How Do I Find The Coordinate For A Double Prime After The Rotation class=

Sagot :

When we rotate a figure 90° around a point, we need to check the difference in x and y coordinates between the point and the center of rotation.

Then these differences will swap among themselves.

The difference in x-coordinate between A and B is 1, so now this difference will be the difference in y-coordinate.

The difference in y-coordinate between A and B is 7, so now this difference will be the difference in y-coordinate.

So the coordinates of A'' will be:

[tex]B(-2,-1)\to A^{\doubleprime}(-2+1,-1+7)=A^{\doubleprime}(-1,6)[/tex]

Also, the point will be in the third quadrant, so all coordinates are negative:

[tex]A^{\doubleprime}(-1,6)\to A^{\doubleprime}(-1,-6)[/tex]

Therefore the answer is C.

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