Answered

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I need some help please out

Sagot :

Question:

Solution:

Let the following equation:

[tex]\sqrt[]{12-x}=\text{ x}[/tex]

this is equivalent to:

[tex](\sqrt[]{12-x})^2=x^2[/tex]

this is equivalent to:

[tex]12-x=x^2[/tex]

this is equivalent to:

[tex]x^2+x-12=\text{ 0}[/tex]

thus, we can conclude that

x= 3.

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