Given:
Probability of few cases is given
Required:
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Explanation:
(a)
[tex]\begin{gathered} the\text{ odds in favor of getting an extra turn=} \\ \\ =\frac{probability\text{ of chances to get an extra turn in 17 attempts}}{probability\text{ of chance to not get an extra turn in 17 attempts}} \\ \\ =\frac{6}{17-6}\text{ =}\frac{6}{11} \end{gathered}[/tex]
(b) Odds against is given by number of failures/number of successes
[tex]\begin{gathered} \frac{no\text{ of failures }}{no\text{ of success}}=\frac{9}{10} \\ \\ The\text{ total number of trials in failures+number of successes= 9+10=19} \\ \\ So\text{ getting a lamon-flavored piece is a success.} \\ \\ p(getting\text{ a lamon flavoured piece\rparen=}\frac{10}{19} \end{gathered}[/tex]
Required answer:
[tex](a)\frac{6}{11}\text{ \lparen b\rparen}\frac{10}{19}[/tex]
