Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

A bottle rocket is launched straight up. Its height in feet (y) above theground x seconds after launch is modeled by the quadratic function: y =-16x2 + 132x + 6.How many seconds did it take the rocket to reach its maximum height?

A Bottle Rocket Is Launched Straight Up Its Height In Feet Y Above Theground X Seconds After Launch Is Modeled By The Quadratic Function Y 16x2 132x 6How Many S class=

Sagot :

Answer:

(C)4.125 seconds

Explanation:

The quadratic function modeling the rocket's movement is:

[tex]y=-16x^2+132x+6[/tex]

To determine the number of seconds it takes the rocket to reach its maximum height, we are being asked to find the equation of the line of symmetry.

For a quadratic function of the form y=ax²+bx+c, the equation of the line of symmetry is:

[tex]x=-\frac{b}{2a}[/tex]

In the given equation:

a = -16, b = 132

Therefore:

[tex]\begin{gathered} x=-\frac{132}{-2\times16} \\ x=4.125 \end{gathered}[/tex]

It takes the rocket 4.125 seconds to reach its maximum height.

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.