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Given the points A(-8,-7) and B(8,5) find the coordinates of point P on directed line segment AB that partitions AB into the ratio 3:1

Sagot :

Given the points A(-8,-7) and B(8,5) find the coordinates of point P on directed line segment AB that partitions AB into the ratio 3:1​

step 1

Find the distance in the x-coordinate between A and B

dABx=(8-(-8)=8+8=16 units

Find the distance in the y-coordinate between A and B

dABy=5-(-7)=5+7=12 units

step 2

we know that

point P on directed line segment AB that partitions AB into the ratio 3:1​

so

AP/AB=3/(3+1)

AP/AB=3/4

Find the x coordinate of point P

APx/ABx=3/4

substitute

APx/16=3/4

APx=16*(3/4)

APx=12 units

The x-coordinate of P is

Px=Ax+APx

where

Ax is the x-coordinate of P

Px=-8+12=4

step 3

Find the y-coordinate of P

we have that

APy/ABy=3/4

substitute

APy/12=3/4

APy=12*(3/4)

APy=9

The y coordinate of P is

Py=APy+Ay

where

Ay is the y-coordinate of P

Py=9+(-7)=2

therefore

the answer is

The coordinate of P are (4,2)

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