The given equation is
[tex]r=2-sin\theta[/tex]To find the incorrect point, we will substitute the value of theta in each point and find the value of r to the nearest 2 decimal points and compare it with the value of r of the point
[tex]\begin{gathered} \theta=0 \\ r=2-sin0 \\ r=2-0 \\ r=2 \end{gathered}[/tex]Answer A is correct
[tex]\begin{gathered} \theta=\frac{\pi}{6} \\ r=2-sin\frac{\pi}{6} \\ r=2-\frac{1}{2} \\ r=1.5 \end{gathered}[/tex]Answer B is correct
[tex]\begin{gathered} \theta=\frac{\pi}{3} \\ r=2-sin\frac{\pi}{3} \\ r=1.13 \end{gathered}[/tex]Since the value of corresponding r is 2.09, then
Answer C is incorrect
The answer is C