Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
1) To plot a linear equation, like y=2x +3 let's visualize the graph
2) Set this function as an equation, to find the root of that function the x coordinate
y= 2x +3 Turn this to an equation
2x +3 =0 Subtract 3 from both sides
2x +3 -3 = -3
2x+0=-3 Divide both sides by 2
x=-3/2 -3/2 = -1.5
Looking at the function, we can see that the slope m=2, m>0, and the y-intercept is 3
Now we can set a table, where we can choose any value for x and then plug it into the function
x = 0 , y = 2(0) +3 y= 3
x= 1, y = 2(1) +3 y= 5
x=-1.5 y = 2(-1.5) +3 y=0
x | y
0 3
1 5
-1.5 0
At least 3 points already determine a line
Our graph must be like this:



Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.