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In circle o, a diameter has endpoints (-5,4) and(3, -6). What is the length of the diameter?Answer choices: a.) sqrt 10b.) 2sqrt 41c.) sqrt 2 d.) 2sqrt 2

Sagot :

Diameter has endpoints (-5,4) and (3, -6).

the endpoints of the diameter = (-5,4) and (3,-6)

The length of diameter can be calculated by sqrt 10,11

Distance between two coordinates (-5,4) and (3,-6).

Distance formula is express as

[tex]\begin{gathered} \text{Distance = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^1^{}} \\ \text{Distance}=\sqrt[]{(3-(-5))+(-6+(4))} \\ \text{Diamter = }\sqrt[]{8-(-2)} \\ \text{Diameter = }\sqrt[]{10} \end{gathered}[/tex]

Diameter = sqrt 10

Answer: Diameter = sqrt 10

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