Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A police officer in hot pursuit drives her car through a circular turn of radius 379 mwith a constant speed of 90.0 km/h. Her mass is 52.0 kg.What are (a) themagnitude and (b) the angle (relative to vertical) of the net force of the officer onthe car seat? (Hint: Consider both horizontal and vertical forces.)

A Police Officer In Hot Pursuit Drives Her Car Through A Circular Turn Of Radius 379 Mwith A Constant Speed Of 900 Kmh Her Mass Is 520 KgWhat Are A Themagnitude class=

Sagot :

The centripetal force keeps the car in the circle. This force is directed towards the center of the circle. The upward force on the police officer is f = mg and the centripetal force is represented as follows

[tex]F_c=\frac{mv^2}{r}[/tex]

The net force will be

[tex]\begin{gathered} F_{net}=F_c+mg \\ F_{net}=\sqrt[]{(\frac{mv^2}{r})^2+(mg)^2} \end{gathered}[/tex]

A.

[tex]\begin{gathered} r=379m \\ m=52.0\text{ kg} \\ \text{speed}=90\text{ km/h} \\ \text{speed}=25\text{ m/s} \\ F_{net}=\sqrt[]{(\frac{52\times25^2}{379})^2+(52\times9.8)^2} \\ F_{net}=\sqrt[]{(\frac{32500}{379})^2+(509.6)^2} \\ F_{net}=\sqrt[]{(85.7519788918)^2+259692.16} \\ F_{net}=\sqrt[]{7353.40188386+259692.16} \\ F_{net}=\sqrt[]{267045.561884} \\ F_{net}=516.764512988 \\ F_{net}\approx516.76N \end{gathered}[/tex]

B.

[tex]\begin{gathered} \tan \emptyset=\frac{\frac{mv^2}{r}}{mg} \\ \tan \emptyset=\frac{mv^2}{r}\times\frac{1}{mg} \\ \tan \emptyset=\frac{v^2}{rg} \\ \tan \emptyset=\frac{25^2}{379\times9.8} \\ \tan \emptyset=\frac{625}{3714.2} \\ \tan \emptyset=0.16827311399 \\ \emptyset=\tan ^{-1}0.16827311399 \\ \emptyset=9.55185382438 \\ \emptyset=9.55^{\circ} \end{gathered}[/tex]

View image KaelaniY771868
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.