Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
[tex]\begin{equation*} =1.29*10^{21}\text{ electrons} \end{equation*}[/tex]
Explanation
An Ampere is in the SI base unit of electric current equal to one coulomb per second.
[tex]\text{ 1 Ampere=}\frac{1\text{ C}}{s}[/tex]and remember that the charge of an electron is
[tex]Q_e=-1.6*10^{-19\text{ }}C[/tex]Step 1
a) let
[tex]\begin{gathered} I=11.37\text{ Amperes} \\ I=11.37\text{ A}*(\frac{\frac{1C}{s}}{A})=11.37\frac{C}{s} \\ also \\ time\text{ =}18.9\text{ s} \end{gathered}[/tex]so
[tex]\begin{gathered} I=\frac{Q}{time} \\ replace \\ 11.37A=\frac{Q}{18.19} \\ multiply\text{ both sides by 18.19} \\ 11.37A*18.19=\frac{Q}{18.19}*18.19 \\ 206.8206\text{ C}=Q \end{gathered}[/tex]b) now , to find the number o f electrons , divide the total a}charge by the charge of an electron
[tex]Number\text{ of electrons=}\frac{206.8206C}{\lvert{-1.6*10^{-19\text{ }}C}\rvert}=1.29*10^{21}\text{ electrons}[/tex]therefore, the answer is
[tex]\begin{equation*} =1.29*10^{21}\text{ electrons} \end{equation*}[/tex]I hope this helps you
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
