Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
[tex]\begin{equation*} =1.29*10^{21}\text{ electrons} \end{equation*}[/tex]
Explanation
An Ampere is in the SI base unit of electric current equal to one coulomb per second.
[tex]\text{ 1 Ampere=}\frac{1\text{ C}}{s}[/tex]and remember that the charge of an electron is
[tex]Q_e=-1.6*10^{-19\text{ }}C[/tex]Step 1
a) let
[tex]\begin{gathered} I=11.37\text{ Amperes} \\ I=11.37\text{ A}*(\frac{\frac{1C}{s}}{A})=11.37\frac{C}{s} \\ also \\ time\text{ =}18.9\text{ s} \end{gathered}[/tex]so
[tex]\begin{gathered} I=\frac{Q}{time} \\ replace \\ 11.37A=\frac{Q}{18.19} \\ multiply\text{ both sides by 18.19} \\ 11.37A*18.19=\frac{Q}{18.19}*18.19 \\ 206.8206\text{ C}=Q \end{gathered}[/tex]b) now , to find the number o f electrons , divide the total a}charge by the charge of an electron
[tex]Number\text{ of electrons=}\frac{206.8206C}{\lvert{-1.6*10^{-19\text{ }}C}\rvert}=1.29*10^{21}\text{ electrons}[/tex]therefore, the answer is
[tex]\begin{equation*} =1.29*10^{21}\text{ electrons} \end{equation*}[/tex]I hope this helps you
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.
