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Sagot :
Given:
height(h)=15 inches
radius(r)=9 inches
Volume of cone:
[tex]V=\pi\times r^2\times\frac{h}{3}[/tex][tex]V=\pi\times9^2\times\frac{15}{3}=\pi\times81\times5[/tex][tex]V=\pi\times405[/tex][tex]V=405\pi\text{ cubic inches}[/tex]
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