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4. I The coordinates of ΔLMN are L(0,-3), M(2,1) and N(7,0). Right the coordinates of L’,M’, and N’ when ΔLMN is under a translation 2 units to the left and 4 units up

4 I The Coordinates Of ΔLMN Are L03 M21 And N70 Right The Coordinates Of LM And N When ΔLMN Is Under A Translation 2 Units To The Left And 4 Units Up class=

Sagot :

Given: The coordinate of triangle LMN as

[tex]\begin{gathered} L(0,-3) \\ M(2,1) \\ N(7,0) \end{gathered}[/tex]

To Determine: The coordinates of the image, L'M'N' under the translation 2 units to the left and 4 units up

The translation rule for a translation of of a units to the left is

[tex](x,y)\rightarrow(x+a,y)[/tex]

The translation rule for translation of b units up is

[tex](x,y)\rightarrow(x,y+b)[/tex]

Therefore, the translation rule of a units to the left and b units up is

[tex](x,y)\rightarrow(x+a,y+b)[/tex]

Applying the rule to given translation of 2 units to the left and 4 units up would be

[tex](x,y)\rightarrow(x+2,y+4)[/tex]

Now, we apply the rule to get the coordinates of the image as shown below

[tex]\begin{gathered} L(0,-3)\rightarrow L^{\prime}(0+2,-3+4)=L^{\prime}(2,1) \\ M(2,1)\rightarrow M^{\prime}(2+2,1+4)=M^{\prime}(4,5) \\ N(7,0)\rightarrow N^{\prime}(7+2,0+4)=N^{\prime}(9,4) \end{gathered}[/tex]

Hence, the coordinate of the image is

L'(2,1)

M' (4,5)

N' (9,4)